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JEE CHEMISTRY MCQ: ALDEHYDES & KETONES & CARBOXYLIC ACIDS

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HCHO+C6H5CHO→con. NaOHproducts  areHCHO + {C_6}{H_5}CHO\xrightarrow[{}]{{con.\,NaOH}}{\text{products}}\,\,{\text{are}}
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Correct option: D
HCOONa+C6H5CH2OHHCOONa + {C_6}{H_5}C{H_2}OH
Option D (HCOONa+C6H5CH2OHHCOONa + {C_6}{H_5}C{H_2}OH) is correct because formaldehyde undergoes oxidation to form formate, while benzaldehyde undergoes reduction to form benzyl alcohol in the Cannizzaro reaction.

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