JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Hard

1 of 1

Application +4 | -1

\theta

lies in the first quadrant and

\cos \theta

=8 / 17

, then the value of

\cos \left(30^{\circ}+\theta\right)+\cos \left(45^{\circ}-\theta\right)+

\cos \left(120^{\circ}-\theta\right)

View answer and explanation

Correct option: A

\left(\frac{\sqrt{3}-1}{2}+\frac{1}{\sqrt{2}}\right) \frac{23}{17}

Option A is correct. By using trigonometric identities and the given value of

\cos \theta

, the expression simplifies to

\left(\frac{{\sqrt{{3}}-1}}{{2}}+\frac{{1}}{{\sqrt{{2}}}}\right) \frac{{23}}{{17}}

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