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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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If I=∫0π/4sin⁡2xdxI=\int\limits_{0}^{\pi / 4} \sin ^2 x d x and J=∫0π/4cos⁡2xdxJ=\int\limits_{0}^{\pi / 4} \cos ^2 x d x, then I=I=
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Correct option: A
π4−J\frac{\pi}{4}-J
Option C is correct because the integrals of sin²(x) and cos²(x) from 0 to π/4 are related by I + J = π/4.

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