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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Analyzing +4 | -1
Let f:R→Rf: R \rightarrow R be a function defined by f(x)=log⁡m{2(sin⁡x−cos⁡x)+m−2}f(x)=\log _{\sqrt{m}}\{\sqrt{2}(\sin x-\cos x)+m-2\}, for some mm, such that the range of ff is [0,2][0,2]. Then the value of mm is
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Correct option: D
5
Option D (5) is correct because the range of the function is [0,2], which leads to the equation log⁡m(m−4)=0\log_{\sqrt{m}}(m-4) = 0, and solving for m gives m = 5.

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