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JEE MATHEMATICS MCQ: LIMITS

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Application +4 | -1
Let f:R→Rf: \mathbb{R} \rightarrow \mathbb{R} be such that f(1)=3f(1)=3 and f′(1)=6f^{\prime}(1)=6. Then

lim⁡x→0(f(1+x)f(1))1/x=\lim \limits_{{x \rightarrow 0}}\left(\frac{f(1+x)}{f(1)}\right)^{1 / x}=
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Correct option: A
e2e^2
Option A (e2e^2) is correct because by taking the natural logarithm and applying L'Hôpital's rule, the limit simplifies to e2e^2.

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