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JEE PHYSICS MCQ: MAGNETISM AND MATTER

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Application +4 | -1

A magnet is parallel to a uniform magnetic field. If it is rotated by

60^\circ

, the work done is

0.8\;J

. How much work is done in moving it

30^\circ

further

View answer and explanation

Correct option: A

0.8 \times {10^7}erg

Option A (

0.8 \times {10^7}erg

) is correct because it calculates the work done using the formula

W = MB(\cos{\theta _1} - \cos{\theta _2})

and converts Joules to ergs.

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Curie temperature is the one above which A vibration magnetometer consists of two identical bar magnets placed one over the other such that they are perpendicular and bisect each other. The time period of oscillation in a horizontal magnetic field is

{2^{5/4}}

s. One of the magnets is removed and if the other magnet oscillates in the same field , then the time period in second is The relative permeability of a substance

X

is slightly less than unity and that of substance

Y

is slightly more than unity, then A bar magnet is equivalent to If the magnetic dipole moment of an atom of diamagnetic material, paramagnetic material and ferromagnetic material are denoted by

\mu_{\mathrm{d}}, \mu_{\mathrm{p}}

\mu_{\mathrm{f}}

respectively, then :- Which of the following is most suitable for the core of electromagnets