JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Application +4 | -1

\lim _{x \rightarrow \infty}\left(\frac{x^2+1}{x+1}-a x-b\right)=0

then

(a, b)

value is

View answer and explanation

Correct option: B

(1,-1)

Option B ((1,-1)) is correct because, for the limit to be 0, the coefficients of

x^2

and

x

in the numerator must be zero, leading to

a=1

and

b=-1

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