$0.2$ g of a sample of ${{\rm{H}}_2}{{\rm{O}}_2}$ required $10$ mL of $N{\rm{KMn}}{{\rm{O}}_4}$ in a titration in the presence of ${{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}{\rm{.}}$. Purity of ${{\rm{H}}_2}{{\rm{O}}_2}$ is :

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JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

1 Medium

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Application +4 | -1

0.2

g of a sample of

{\mathrm{H}_2}{\mathrm{O}_2}

required

10

mL of

N\mathrm{KMn}{\mathrm{O}_4}

in a titration in the presence of

{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}\mathrm{.}

. Purity of

{\mathrm{H}_2}{\mathrm{O}_2}

is :

View answer and explanation

Correct option: B

85\%

Option B (

85\%

) is correct because the purity is calculated by determining the mass of H2O2 that reacted with KMnO4 and then finding the percentage of that mass in the original sample.

JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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