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JEE CHEMISTRY MCQ: ALDEHYDES & KETONES & CARBOXYLIC ACIDS

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R−COOH→2) H3O+1) LiAlH4/eitherproduct isR - COOH\xrightarrow[{2)\,{H_3}{O^ + }}]{{1)\,LiAl{H_4}/either}}{\text{product}}\,{\text{is}}
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Correct option: A
R−CH2−OHR - C{H_2} - OH
Option A (R−CH2−OHR - C{H_2} - OH) is correct because LiAlH4LiAl{H_4} reduces carboxylic acids to primary alcohols.

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