${R_3}{\rm{SiCl}}$ on hydrolysis forms:

${R_3}{\rm{Si}} - {\rm{O}} - {\rm{Si}}{R_3}$

NEET UG CHEMISTRY MCQ: 14 TH GROUP ELEMENTS (P-BLOCK)

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Understanding +4 | -1

{R_3}\mathrm{SiCl}

on hydrolysis forms:

View answer and explanation

Correct option: B

{R_3}\mathrm{Si} - \mathrm{O} - \mathrm{Si}{R_3}

Option B (

{R_3}\mathrm{Si} - \mathrm{O} - \mathrm{Si}{R_3}

) is correct because the initial product R3SiOH is unstable and undergoes condensation to form R3Si-O-SiR3.

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