$\mathrm{KMnO}_4$ reacts with $\mathrm{KI}$, in weakly basic medium to form $\mathrm{I}_2$ and $\mathrm{MnO}_2$. When $250 \mathrm{~ml}$ of $0.1 \mathrm{M} \mathrm{~KI}$ solution reacts with $250 \mathrm{~mL}$ of $0.02 \mathrm{~M} \mathrm{~KMnO}_4$ in basic medium, what is the number of moles of $I_2$ formed?

NEET UG CHEMISTRY MCQ: d & f- BLOCK ELEMENTS

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Application +4 | -1

\mathrm{KMnO}_4

reacts with

\mathrm{KI}

, in weakly basic medium to form

\mathrm{I}_2

and

\mathrm{MnO}_2

. When

250 \mathrm{~ml}

0.1 \mathrm{M} \mathrm{~KI}

solution reacts with

250 \mathrm{~mL}

0.02 \mathrm{~M} \mathrm{~KMnO}_4

in basic medium, what is the number of moles of

I_2

formed?

View answer and explanation

Correct option: B

0.0075

Option B (

0.0075

) is correct because it represents the number of moles of

I_2

formed based on the stoichiometry of the reaction between

KMnO_4

and

KI

in a weakly basic medium.