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NEET UG PHYSICS MCQ: WORK-ENERGY-POWER

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A steel ball of mass 5 g is thrown downward with velocity 10  ms−110\;\mathrm{m}{\mathrm{s}^{ - 1}} from height 19.5 m. It penetrates sand by 50 cm. The change in mechanical energy will be (g=10  ms−2)\left( {\mathrm{g} = 10\,\,\mathrm{m}{\mathrm{s}^{ - 2}}} \right)
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Correct option: B
1.25 J
Option B (1.25 J) is correct because the change in mechanical energy is the difference between the initial mechanical energy and the final potential energy, accounting for the work done against resistive forces.

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