JEE MATHEMATICS MCQ: SET THEORY

1 Easy

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Analyzing +4 | -1

n\left( {A \cap B} \right) = 10,n\left( {B \cap C} \right) = 20{\text{ }}n\left( {A \cap C} \right) = 30,

then the greatest possible value of

n\left( {A \cap B \cap C} \right)

View answer and explanation

Correct option: C

Option C (10) is correct because the greatest possible value of

n(A \cap B \cap C)

is limited by the smallest of

n(A \cap B)

n(B \cap C)

, and

n(A \cap C)

, which is 10.

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S

2 a_1 a_2 a_3 \ldots . . a_{2006}

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S

a N=\{a n: n \in N: b N=\{n b: n \in N\}

c N=\{c N: n \in N\}

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a, b, c \in N

b, c

A=\{x: x

\}

B=\{x: x

A-B

F(n)

n

[\mathrm{F}(20) \cap \mathrm{F}(16)] \subseteq \mathrm{F}(\mathrm{y})

40 \%

A, 20 \%

10 \%

C

A

C

4 \%

A

C

2 \%

A