Back to CHEMICAL BONDING & MOLECULAR STRUCTURE

JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

1 Easy

1 of 1

Remembering +4 | -1

Hybridisation involves

View answer and explanation

Correct option: B

Mixing up of atomic orbitals

Option B (Mixing up of atomic orbitals) is correct because hybridization is the process of mixing atomic orbitals to form new hybrid orbitals with different energies, shapes, etc.

More Questions from CHEMICAL BONDING & MOLECULAR STRUCTURE

Practice All Chapter MCQs →

The hybridization in sulphur dioxide is

\mathrm{C}{\mathrm{O}_2}

has the same geometry as:

\left( A \right)\mathrm{HgC}{\mathrm{l}_2},\left( B \right)\mathrm{N}{\mathrm{O}_2},\left( C \right)\mathrm{SnC}{\mathrm{l}_4},\left( D \right){\mathrm{C}_2}{\mathrm{H}_2}

The pair of molecules forming strongest hydrogen bonds are Paramagnetism is shown by Which statement is correct? Assertion (A) :

{BF}_3

is a weaker Lewis acid than

{BCl}_3

.

Reason (R) : The planar

{BF}_3

molecule is stabilised to a greater extent than

{BCl}_3

{B}-X \pi

-bonding.