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JEE MATHEMATICS MCQ: LIMITS

1 Hard
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Application +4 | -1
Limx→0(1+2+3+........+[1∣x∣])\mathop {{\text{Lim}}}\limits_{x \to 0} \left( {1 + 2 + 3 + ........ + \left[ {\frac{1}{{\left| {\text{x}} \right|}}} \right]} \right) where [.] denotes greatest integer function , is equal to
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Correct option: B
12\frac{1}{2}
Option B (12\frac{1}{2}) is correct. By evaluating the limit as x approaches 0, the expression converges to 12\frac{1}{2}.

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