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NEET UG PHYSICS MCQ: SYSTEM OF PARTICLES

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A uniform rod of length

\mathrm{L}=60 \mathrm{~cm}

is suspended through an end and is set into oscillation with small amplitude under gravity. Find the time period of oscillation.

\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)

View answer and explanation

Correct option: A

0.4 \pi \mathrm{s}

Option A (

0.4 \pi \mathrm{s}

) is correct because it is the time period of a physical pendulum oscillating with small amplitude.

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