JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

1 Hard

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Application +4 | -1

Calculate the velocity of an electron having wavelength of 0.15 nm Mass of an electron is

9.109 \times {10^{ - 28}}g

\left( {h = 6.626 \times {{10}^{ - 27}}\,erg - s} \right)

View answer and explanation

Correct option: C

4.84 \times {10^8}\mathrm{cm}.{\mathrm{s}^{ - 1}}

Option C (

4.84 \times {10^8}\mathrm{cm}.{\mathrm{s}^{ - 1}}

) is correct because it is the velocity of the electron calculated using the de Broglie wavelength equation.

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\times 10^{12}

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1.25 \times {10^{ - 13}} \times {A^{1/3}}\mathrm{cm}.