JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF SOLIDS

1 Medium

1 of 1

Application +4 | -1

0.1

kg mass is suspended from a wire of negligible mass. The length of the wire is

1\mathrm{ }m

and its cross-sectional area is

4.9 \times {10^{ - 7}}{\mathrm{m}^{2.}}

If the mass is pulled a little in the vertically downward direction and released, it performs simple harmonic motion of angular frequency

140\,\,\mathrm{rad}{\mathrm{s}^{ - 1}}

. If the Young’s modulus of the material of the wire is

n \times {10^9}\,\mathrm{N}{\mathrm{m}^{ - 2}}

, the value of

n

View answer and explanation

Correct option: A

Option A (4) is correct because the Young's modulus is calculated using the formula for the angular frequency of SHM in a wire, and solving for n.

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