${\text{Phenol}}\xrightarrow{{{\text{ Zinc Distillation }}}}(A)\xrightarrow{{{\text{ }}\begin{array}{*{20}{c}} {{\text{Conc}}{\text{.}}\,\,HN{O_3}} \\ {{\text{Conc}}{\text{. }}{H_2}S{O_4}{\text{ at }}{{60}^\circ }{\text{C}}} \end{array}}}\left( B \right)$ In the above reaction, compounds $(A)$ and $(B)$ are:

JEE CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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{\text{Phenol}}\xrightarrow{{{\text{ Zinc Distillation }}}}(A)\xrightarrow{{{\text{ }}\begin{array}{cccccccccccccccccccc} {{\text{Conc}}{\text{.}}\,\,HN{O_3}} \\ {{\text{Conc}}{\text{. }}{H_2}S{O_4}{\text{ at }}{{60}^\circ }{\text{C}}} \end{array}}}\left( B \right)

In the above reaction, compounds

(A)

and

(B)

are:

View answer and explanation

Correct option: D

benzene and nitrobenzene

Option D (benzene and nitrobenzene) is correct because phenol on zinc distillation gives benzene, which on nitration with conc.

HNO_3

and conc.

H_2SO_4

at 60°C gives nitrobenzene.