JEE MATHEMATICS MCQ: SET THEORY

1 Easy

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Analyzing +4 | -1

A = \left\{ {\left( {x,y} \right):{y^2} = x;x,y \in R} \right\}

and

B = \left\{ {\left( {x,y} \right):y = \left| x \right|;x,y \in R} \right\},

then

View answer and explanation

Correct option: D

A \cap B

contains three elements only

Option D (

A \cap B

contains three elements only) is correct because the graphs of y² = x and y = |x| intersect at three points: (0, 0), (1, 1), and (1, -1).

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2 a_1 a_2 a_3 \ldots . . a_{2006}

a_1, a_2, a_3, \ldots ., a_{2006}

S

a N=\{a n: n \in N: b N=\{n b: n \in N\}

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\}

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F(n)

n

[\mathrm{F}(20) \cap \mathrm{F}(16)] \subseteq \mathrm{F}(\mathrm{y})

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A, 20 \%

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C

A

C

4 \%

A

C

2 \%

A