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JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1
The value of lim⁡x→1(log⁡22x)log⁡x5\lim\limits_{x \to 1} {\left( {{{\log }_2}2x} \right)^{{{\log }_x}5}} is
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Correct option: B
elog⁡25{e^{{{\log }_2}5}}
Option B (elog⁡25{e^{{{\log }_2}5}}) is correct because after applying logarithmic properties and simplifying, the limit evaluates to elog⁡25{e^{{{\log }_2}5}}.

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