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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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Application +4 | -1
Electric field strength due to a point charge of 10  μC10\,\,\mu C at a distance of 80 cm from the charge is [N/C][N/C]
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Correct option: D
1.4×1051.4 \times {10^5}
Option D (1.4×1051.4 \times {10^5}) is correct because it is the electric field strength calculated using the formula E=14π∈0Qd2E = \frac{1}{{4\pi { \in _0}}}\frac{Q}{{{d^2}}} with the given charge and distance.

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