Given that $n$ AM’s are inserted between two sets of numbers $a,\;2b\;{\rm{and}}\;2a,\;b\;{\rm{where}}\;a,\;b \in R.$. Suppose further that $m$th mean between these sets of numbers is same, then the ratio $a\;:b$ equals

$n\;:\left( {n - m + 1} \right)$

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

Given that

n

AM’s are inserted between two sets of numbers

a,\;2b\;\mathrm{and}\;2a,\;b\;\mathrm{where}\;a,\;b \in R.

. Suppose further that

m

th mean between these sets of numbers is same, then the ratio

a\;:b

equals

View answer and explanation

Correct option: D

m\;:\left( {n - m + 1} \right)

Option D (

m : (n - m + 1)

) is correct because it represents the ratio

a:b

derived from equating the

m

th means of the two sets of numbers.

Practice All Chapter MCQs →

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\frac{3}{4}