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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1
Let a,  p,  q,  r,  s∈R  ∼  {0}.a,\;p,\;q,\;r,\;s \in R\; \sim \;\left\{ 0 \right\}.

If 3a2+2(1p−1s)a+1p2+1q2+1r2−2(1pq+1qr+1rs)≤03{a^2} + 2\left( {\frac{1}{p} - \frac{1}{s}} \right)a + \frac{1}{{{p^2}}} + \frac{1}{{{q^2}}} + \frac{1}{{{r^2}}} - 2\left( {\frac{1}{{pq}} + \frac{1}{{qr}} + \frac{1}{{rs}}} \right) \le 0 for some real a,a, then p,  q,  r,  sp,\;q,\;r,\;s are in
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Correct option: C
HP
Option C (HP) is correct because the given inequality implies that the reciprocals of p, q, r, and s are in arithmetic progression, thus p, q, r, and s are in harmonic progression.

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