JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

The minimum value of the function

f(x)=\tan x+\cot x

in the interval

(0, \pi / 2)

View answer and explanation

Correct option: C

Option C (2) is correct because the minimum value of the function occurs at x=

\pi

/4, where the function value is 2.

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\frac{{dy}}{{dx}}

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