JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1

The area bounded by curves

y=\cos x

and

y=\sin x

and ordinates

x=0

and

x=\frac{\pi}{4}

View answer and explanation

Correct option: C

\sqrt{2}-1

Option C (

\sqrt{2}-1

) is correct because the area bounded by the curves

y=\cos x

and

y=\sin x

and ordinates

x=0

and

x=\frac{\pi}{4}

is found by integrating the difference of the functions from 0 to

\frac{\pi}{4}

, which results in

\sqrt{2}-1

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