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JEE MATHEMATICS MCQ: PARABOLA

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Application +4 | -1
Normals at two points (x1,y1)\left(x_1, y_1\right) and (x2,y2)\left(x_2, y_2\right) of the parabola y2=4xy^2=4 x meet again on the parabola, where x1+x2=4x_1+x_2=4, then āˆ£y1+y2āˆ£\left|y_1+y_2\right| is equal to
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Correct option: C
424 \sqrt{2}
Option C (424 \sqrt{2}) is correct because it is derived from the given condition x1+x2=4x_1 + x_2 = 4 and the properties of the parabola y2=4xy^2 = 4x.

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The equation of a common tangent to the parabolas y=x2y=x^2 and y=āˆ’(xāˆ’2)2y=-(x-2)^2 is A point PP moves such that slope of one tangent drawn from it to parabola y2=16xy^2=16 x is four times the slope of other tangent, then the length of latus rectum of the conic represented by locus of PP, is Let P,Q,RP,Q,R be three points on parabola y2=4x{y^2} = 4x and normal at PP and RR meet at QQ, then the locus of the mid-point of the chord PRPR is a parabola whose vertex is at The tangents at the end points of any chord through (1,0)(1,0) to the parabola y2+4x=8y^2+4 x=8 intersect The focus of the parabola x2=āˆ’16yx^2=-16 y is If II denotes the semi-latusrectum of the parabola y2=4ax{y^2} = 4ax and SPSP and SQSQ denote the segments of any focal chord PQ,SPQ,S being the focus, then SP,lSP,l and SQSQ are in the relation
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