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JEE MATHEMATICS MCQ: RATE MEASURE

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Application +4 | -1

If the volume of a spherical ball is increasing at the rate of

4 \pi \mathrm{cc} / \mathrm{sec}

, then the rate of increase of its radius (in cm/sec), when the volume is

288 \pi \mathrm{cc}

,

View answer and explanation

Correct option: C

\frac{1}{36}

Option C (

\frac{{1}}{{36}}

) is correct because it is the rate of increase of the radius when the volume is

288 \pi

cc.

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