What would happen when a small quantity of ${{\rm{H}}_2}{{\rm{O}}_2}$ is added to a solution of ${\rm{FeS}}{{\rm{O}}_4}$?

An electron is lost by ${\rm{F}}{{\rm{e}}^{2 + }}$

An electron is added to ${\rm{F}}{{\rm{e}}^{2 + }}$

JEE CHEMISTRY MCQ: REDOX REACTIONS

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Understanding +4 | -1

What would happen when a small quantity of

{\mathrm{H}_2}{\mathrm{O}_2}

is added to a solution of

\mathrm{FeS}{\mathrm{O}_4}

View answer and explanation

Correct option: D

An electron is lost by

\mathrm{F}{\mathrm{e}^{2 + }}

Option D (An electron is lost by

\mathrm{F}{\mathrm{e}^{2 + }}

) is correct because

{\mathrm{H}_2}{\mathrm{O}_2}

acts as an oxidizing agent, oxidizing

\mathrm{F}{\mathrm{e}^{2 + }}

\mathrm{F}{\mathrm{e}^{3 + }}

Practice All Chapter MCQs →

\mathrm{H}

2 \mathrm{KClO}_3 \longrightarrow 2 \mathrm{KCl}+3 \mathrm{O}_2

\mathrm{HNO}_3

\mathrm{HNO}_3

\mathrm{MnO}_4^{-}(\mathrm{aq})+\mathrm{Br}^{-}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{MnO}_2(\mathrm{aq})+\mathrm{BrO}_3^{-}(\mathrm{aq})+2 \mathrm{OH}^{-}(\mathrm{aq})

\mathrm{Br}

-1

+5.