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NEET UG BIOLOGY MCQ: PRINCIPLE OF INHERITANCE AND VARIATION
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An individual homozygous for genes is crossed with wild type and crossed back with
the double recessive. The appearance of the offspring is as follows.
The distance between the genes and is
the double recessive. The appearance of the offspring is as follows.
The distance between the genes and is
View answer and explanation
Correct option: D
10 map units
Option D (10 map units) is correct because the recombination frequency is calculated as (number of recombinants / total offspring) * 100, which in this case is ((98 + 102) / (903 + 897 + 98 + 102)) * 100 = 10.
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