Back to ELECTRIC POTENTIAL AND CAPACITANCE

JEE PHYSICS MCQ: ELECTRIC POTENTIAL AND CAPACITANCE

1 Medium

1 of 1

Application +4 | -1

Two charges of

4\;\mu C

each are placed at the corners

A

and

B

of an equilateral triangle of side length

0.2\;m

in air. The electric potential at

C

is

\left[ {\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {{10}^9}\frac{{N - {m^2}}}{{{C^2}}}} \right]

View answer and explanation

Correct option: C

36 \times {10^4}\;V

Option C (

36 \times {10^4}\,V

) is correct because the electric potential at point C is the sum of the potentials due to each charge at A and B.

More Questions from ELECTRIC POTENTIAL AND CAPACITANCE

Practice All Chapter MCQs →

The potential at a point distance

x

\mu \mathrm{m}

) due to some charges situated on the

x

axis is given by

V(x)=\frac{20}{x^2-5} \mathrm{V}

. The electric field at

x=5 \mu \mathrm{m}

is given by: A parallel plate capacitor is connected to a 5V battery and charged. The battery is then disconnected and a glass slab is introduced between the plates. Then, the quantities that decrease are A conducting sphere of radius

R

is given a charge

Q

. The electric potential and the electric field at the centre of the sphere respectively are Two capacitors when connected in series have a capacitance of

3\mu F,\,

and when connected in parallel have a capacitance of

16\mu F

. Their individual capacities are Statement-1: If temperature is increased, the dielectric constant of a polar dielectric decreases whereas that of a non-polar dielectric does not change significantly.
Statement-2: The magniude of dipole moment of individual polar molecule decreases significantly with increase in temperature. An electric dipole when placed in a uniform electric field

E

will have minimum potential energy, if the positive direction of dipole moment makes the following angle with

E