The product C in the following sequence of reaction, ${{\rm{C}}_2}{{\rm{H}}_5}{\rm{Br}}\xrightarrow{{{\rm{NaOH\;}}\left( {aq} \right)}}A\mathop \to \limits^{{\rm{Na}}} B\xrightarrow{{{\rm{C}}{{\rm{H}}_3}{\rm{I}}}}C$ is:

JEE CHEMISTRY MCQ: ALCOHOLS & PHENOLS & ETHERS

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The product C in the following sequence of reaction,

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{Br}\xrightarrow{{\mathrm{NaOH\;}\left( {aq} \right)}}A\mathop \to \limits^{\mathrm{Na}} B\xrightarrow{{\mathrm{C}{\mathrm{H}_3}\mathrm{I}}}C

is:

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Correct option: C

Methyl ethyl ether

Option C (Methyl ethyl ether) is correct because the sequence of reactions leads to the formation of an ether via Williamson ether synthesis.