If $c^2=a^2+b^2$, then $4 s(s-a)(s-b)(s-c)$ is equal to

JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Application +4 | -1

c^2=a^2+b^2

, then

4 s(s-a)(s-b)(s-c)

is equal to

View answer and explanation

Correct option: D

a^2 b^2

Option D (

a^2 b^2

) is correct because the area of a right-angled triangle with sides a and b is

\frac{1}{2}ab

, and

4(\frac{1}{2}ab)^2 = a^2b^2

Practice All Chapter MCQs →

{p_1},{p_2},{p_3}

\Delta \;ABC

A,B,C

\Delta

p_1^{ - 2} + p_2^{ - 2} + p_3^{ - 2}

5k,\;6k,\;5k

k

\Delta \,ABC

a = \left( {b - c} \right)\sec \theta

\frac{{2\,\sqrt {bc} }}{{b - c}}\,\,\sin \,\,\frac{A}{2} =

\Delta \;ABC,\frac{{b + c}}{a}

\Delta = {a^2} - {\left( {b - c} \right)^2}

\Delta

\Delta \;ABC

\tan A

A

2 s