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JEE MATHEMATICS MCQ: PARABOLA

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Application +4 | -1
If line y=2x+cy=2 x+c is a normal to the parabola y2=4xy^2=4 x at the point (t2,2t)\left(t^2, 2 t\right) then
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Correct option: A
c=−12,t=−2c=-12, t=-2
Option A (c=-12, t=-2) is correct because substituting the normal equation into the given line equation and comparing coefficients yields these values for c and t.

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