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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1
Solve the equations for xx and y:y:

xcos⁡3y+3xcos⁡ysin⁡2y=14xsin⁡3y+3xcos⁡2ysin⁡y=13\begin{aligned} & x \cos ^3 y+3 x \cos y \sin ^2 y=14 \\ & x \sin ^3 y+3 x \cos ^2 y \sin y=13 \end{aligned}
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Correct option: C
Both
Option C (Both) is correct because by dividing and using componendo and dividendo, we find two possible solutions for x and y that satisfy the given conditions.

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