NEET UG PHYSICS MCQ: SEMI CONDUCTOR DEVICES

1 Medium

1 of 1

Understanding +4 | -1

For a junction diode the ratio of forward current

\left( {{I_F}} \right)

and reverse current

\left( {{I_r}} \right)

is

[

{I_e} =

electronic charge,

V =

voltage applied across junction,

k =

Boltzmann constant,

T =

temperature in kelvin]

View answer and explanation

Correct option: D

\left( {{e^{V/kT}} - 1} \right)

Option D

\left( {{e^{V/kT}} - 1} \right)

is correct because this is the Shockley diode equation which relates forward and reverse current.

More Questions from SEMI CONDUCTOR DEVICES

Practice All Chapter MCQs →

I = A{T^2}{e^{q/{V_L}}}

{V_L}

\sqrt{n}.

n

p - n\;

{10^{17}}\mathrm{c}{\mathrm{m}^{ - 3}}

P

{10^{16}}

\mathrm{c}{\mathrm{m}^{ - 3}}

N

kT =

{n_i} = 1.4 \times {10^{10}}

\mathrm{c}{\mathrm{m}^{ - 3}}