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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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If ∫sin⁡x1t2f(t)dt=1−sin⁡x\int\limits_{{\sin x}}^1 t^2 f(t) d t=1-\sin x for all x∈[0,π/2]x \in[0, \pi / 2], then f(13)=f\left(\frac{1}{\sqrt{3}}\right)=
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Correct option: A
3
Option C (3) is correct because differentiating both sides using Leibniz's rule and solving for f(x)f(x) gives f(13)=3f(\frac{{1}}{{\sqrt{{3}}}})=3.

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