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JEE MATHEMATICS MCQ: MULTIPLE AND SUBMULTIPLE ANGLES

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sin⁡23 Asin⁡2 A−cos⁡23 Acos⁡2A=\frac{{{{\sin }^2}3\,A}}{{{{\sin }^2}\,A}} - \frac{{{{\cos }^2}3\,A}}{{{{\cos }^2}A}} =
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Correct option: B
8  cos⁡  2A8\;\cos \,\,2A
Option B (8  cos⁡  2A8\;\cos \;2A) is correct because the expression simplifies to 8cos⁡2A8\cos 2A using trigonometric identities.

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