JEE PHYSICS MCQ: NUCLEI

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Application +4 | -1

In a reactor, 2kg of

_{92}{U^{235}}

fuel is fully used up in 30 days. The energy released per fission is 200 MeV.
Given that, the Avogadro number,

N = 6.023 \times {10^{26}}{K^{ - 1}}\,mo{l^{ - 1}}

and

1\,\,eV = 1.6 \times {10^{ - 19}}J.

The power output of the reactor is close to

View answer and explanation

Correct option: C

60 MW

Option C (60 MW) is correct because it is the closest value to the calculated power output of the reactor, considering the energy released per fission and the amount of fuel used.

JEE PHYSICS MCQ: NUCLEI

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