If $\cos \,\,p\;\theta = \cos \,\,q\;\theta ,\,\,p \ne q$ then

$\theta = 2\;n\;\pi ,\,\,n \in Z$

$\theta = \frac{{n\;\pi }}{{p + q}},\,\,n \in Z$

JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

\cos \,\,p\;\theta = \cos \,\,q\;\theta ,\,\,p \ne q

then

View answer and explanation

Correct option: B

\theta = \frac{{2\;n\;\pi }}{{p \pm q}},\,\,n \in Z

Option B (

\theta = \frac{{2\;n\;\pi }}{{p \pm q}},\\,\,n \in Z

) is correct because it represents the general solution for the given trigonometric equation using the properties of cosine function.

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