JEE MATHEMATICS MCQ: PARABOLA

1 Medium

1 of 1

Analyzing +4 | -1

Let

f(x)=3 x^2-7 x+c

, where '

{c}

' is a variable co-efficient and

x > \frac{7}{6}

. The value of '

{c}

' such that

f(x)

touches

f^{-1}(x)

is.....

View answer and explanation

Correct option: C

\frac{16}{3}

Option C (

\frac{{16}}{{3}}

) is correct because f(x) touches f⁻¹(x) when f(x) = x, and solving the resulting quadratic equation with equal roots yields c = 16/3.

More Questions from PARABOLA

Practice All Chapter MCQs →

y=x^2

y=-(x-2)^2

P

y^2=16 x

P

P,Q,R

{y^2} = 4x

P

R

Q

PR

(1,0)

y^2+4 x=8

x^2=-16 y

I

{y^2} = 4ax

SP

SQ

PQ,S

SP,l

SQ