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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Analyzing +4 | -1
Let f(x)=sin⁡−1(sin⁡x)f(x)=\sin ^{-1}(\sin x) and g(x)=cos⁡−1[x+1]+sin⁡−1[x]g(x)=\cos ^{-1}[x+1]+\sin ^{-1}[x]. Then the number of solution of f(x)+g(x)=4f(x)+g(x)=4, lies in the interval

(where [∗]\left[{ }^*\right] denotes the greatest integer function)
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Correct option: C
(−2,1)(-2,1)
Option C, (−2,1)(-2,1), is correct because the domain of g(x) is [-1, 1) and within this domain, g(x) = 0, leading to no solution for f(x) + g(x) = 4.

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