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JEE CHEMISTRY MCQ: AMINES

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Application +4 | -1
In the given reaction what will be the product

Rβˆ’NHβˆ’COβˆ£βˆ£βˆ’Hβ†’PyridinePOCl3ProductR - NH - \mathop C\limits^{\begin{array}{cccccccccccccccccccc} O \\ {||} \end{array}} - H\xrightarrow[{Pyridine}]{{POC{l_3}}}{\text{Product}}
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Correct option: B
Rβˆ’N+≑Cβˆ’{R}-\stackrel{+}{{N}} \equiv {C}^{-}
Option B (Rβˆ’N+≑Cβˆ’{R}-\stackrel{+}{{N}} \equiv {C}^{-}) is correct because N-alkyl formamides, when dehydrated with POCl3{POCl}_3 in the presence of pyridine, give isocyanides.

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