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JEE MATHEMATICS MCQ: SCALAR TRIPLE PRODUCT

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Application +4 | -1

Given vectors

\mathbf{a}, \mathbf{b}, \mathbf{c}

such that

\mathbf{a}(\mathbf{b} \times \mathbf{c})=\lambda \neq 0

, the value of

(\mathbf{b} \times \mathbf{c}) .(\mathbf{a}+\mathbf{b}+\mathbf{c}) / \lambda

is

View answer and explanation

Correct option: C

-3 \lambda

Option B (1) is correct because

(\mathbf{b} \times \mathbf{c}) .(\mathbf{a}+\mathbf{b}+\mathbf{c}) / \lambda

simplifies to

\lambda / \lambda = 1

since

(\mathbf{b} \times \mathbf{c}) . \mathbf{b}

and

(\mathbf{b} \times \mathbf{c}) . \mathbf{c}

are zero.

More Questions from SCALAR TRIPLE PRODUCT

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\vec r\cdot\vec a = \vec r\cdot\vec b = \vec r\cdot\vec c = 0

for some non-zero vector

\vec r,

then the value of

\left[ {\vec a\vec b\vec c} \right],

is The shortest distance between the lines

\frac{{x - 3}}{2} = \frac{{y - 2}}{3} = \frac{{z - 1}}{{ - 1}}

\frac{{x + 3}}{2} = \frac{{y - 6}}{1} = \frac{{z - 5}}{3},

\mathbf{\vec a} = \widehat \mathbf{i} - \mathbf{\hat k},\;\mathbf{\vec b} = x\widehat \mathbf{i} + \widehat \mathbf{j} + \left( {1 - x} \right)\mathbf{\hat k}

\mathbf{\vec c} = y\widehat \mathbf{i} + x\widehat \mathbf{j} + \left( {1 + x - y} \right)\mathbf{\hat k}.

\left[ {\mathbf{\vec a},\;\mathbf{\vec b},\;\mathbf{\vec c}} \right]

\vec{a}, \vec{b}

are non-zero vectors, then

((\vec{a} \times \vec{b}) \times \vec{a}) \cdot((\vec{b} \times \vec{a}) \times \vec{b})

a \cdot(a \times b)=

The length of the perpendicular from the origin to the plane passing through the point a and containing the line

\mathbf{r}=\mathbf{b}+\lambda \mathbf{c}