JEE MATHEMATICS MCQ: ELLIPSE

1 Medium

1 of 1

Understanding +4 | -1

\mathrm{\theta }

and

\phi

are eccentric angle of the ends of a pair of conjugate diameters of the ellipse

\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1

, then

\mathrm{\theta } - \phi

is equal to

View answer and explanation

Correct option: A

\pm \,\frac{\pi }{2}

Option A (10) is correct because the sum of the focal distances of any point on the ellipse is equal to the length of the major axis, which is

2a = 10

More Questions from ELLIPSE

Practice All Chapter MCQs →

\frac{x^2}{144}+\frac{y^2}{81}=1

m

\mathrm{M}

\mathrm{mM}

P

\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1

S

S'.

A

PSS',

A

A

B

(\sqrt{7}, 0)

(-\sqrt{7}, 0)

P

9 x^{2}+16 y^{2}=144

\mathrm{PA}+\mathrm{PB}

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

r

\frac{x^2}{25}+\frac{y^2}{16}=1

P

x=0

Q

R

Q

y=x

Q

R

N P

Q

P

O