JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Analyzing +4 | -1

x > 0

\lim\limits_{x \to 0} \left( {{{\left( {\sin x} \right)}^{\frac{1}{x}}} + {{\left( {\frac{1}{x}} \right)}^{\sin x}}} \right)

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Correct option: C

Option C (

\sin 1

) is correct. The limit is found by evaluating the left-hand limit and right-hand limit separately and showing that they are equal to

\sin 1

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