The maximum and minimum distances of a comet from the sun are $1.4 \times {10^{12}}m\,and\,6 \times {10^{10}}m$ respectively. If its velocity nearest to the sun is $7 \times {10^4}{\rm{m}}{{\rm{s}}^{ - 1}}$, what is the velocity in the farthest position? Assume the paths of comet in both instantaneous positions are circular

$3 \times {10^3}{\rm{m}}{{\rm{s}}^{ - 1}}$

$5 \times {10^3}{\rm{m}}{{\rm{s}}^{ - 1}}$

$7 \times {10^3}{\rm{m}}{{\rm{s}}^{ - 1}}$

NEET UG PHYSICS MCQ: GRAVITATION

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The maximum and minimum distances of a comet from the sun are

1.4 \times {10^{12}}m\,and\,6 \times {10^{10}}m

respectively. If its velocity nearest to the sun is

7 \times {10^4}\mathrm{m}{\mathrm{s}^{ - 1}}

, what is the velocity in the farthest position? Assume the paths of comet in both instantaneous positions are circular

View answer and explanation

Correct option: A

3 \times {10^3}\mathrm{m}{\mathrm{s}^{ - 1}}

Option A (

3 \times {10^3}\mathrm{m}{\mathrm{s}^{ - 1}}

) is correct because angular momentum is conserved, and the velocity is inversely proportional to the distance.