The set of all $x$ in $(-\pi, \pi)$ satisfying $|4 \sin x-1| < \sqrt{5}$ is given by

$x \in\left(-\frac{\pi}{10}, \pi\right)$

$x \in\left(-\pi, \frac{3 \pi}{10}\right)$

JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

The set of all

x

(-\pi, \pi)

satisfying

|4 \sin x-1| < \sqrt{5}

is given by

View answer and explanation

Correct option: B

x \in\left(-\frac{\pi}{10}, \frac{3 \pi}{10}\right)

Option B (

x \in(-\frac{\pi}{10}, \frac{3 \pi}{10})

) is correct because solving the inequality

|4 \sin x-1| < \sqrt{5}

within the interval

(-\pi, \pi)

leads to this solution set.

Practice All Chapter MCQs →

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