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JEE PHYSICS MCQ: OSCILLATIONS

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A pendulum having time period equal to two seconds is called a seconds pendulum. Those used in pendulum clocks are of this type. Find the length of a seconds pendulum at a place where g=π2 m s−2g=\pi^2 \mathrm{~m} \mathrm{~s}^{-2}.
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Correct option: A
1 cm
The correct answer is 1 cm because the length of a seconds pendulum is calculated using the formula T=2πlgT = 2\pi\sqrt{\frac{l}{g}} with T=2T=2 seconds and g=π2 m s−2g=\pi^2 \mathrm{~m} \mathrm{~s}^{-2}.

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