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JEE PHYSICS MCQ: GRAVITATION

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Four particles of masses m,2m,3mm, 2 m, 3 m and 4m4 m are kept in sequence at the corners of a square of side aa. The magnitude of gravitational force acting on a particle of mass m\mathrm{m} placed at the centre of the square will be
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Correct option: C
42Gm2a2\frac{4 \sqrt{2} G m^2}{a^2}
Option C (42Gm2a2\frac{{4 \sqrt{{2}} G m^2}}{{a^2}}) is correct because it represents the net gravitational force calculated by vectorially summing the forces from each mass at the corners of the square.

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